-9.8x^2+45x+1=0

Solution for -9.8x^2+45x+1=0 equation:

-9.8x^2+45x+1=0

a = -9.8; b = 45; c = +1;
Δ = b2-4ac
Δ = 452-4·(-9.8)·1
Δ = 2064.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2064.2}}{2*-9.8}=\frac{-45-\sqrt{2064.2}}{-19.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2064.2}}{2*-9.8}=\frac{-45+\sqrt{2064.2}}{-19.6}
$